Math, asked by Anonymous, 1 year ago

plzzzzzzz help me guys ​

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Answered by rocky200216
5

\sf{\underbrace{\red{SOLUTION:-}}}

 {( - x + 4y)}^{2}  +  {( - x - 4y)}^{2}  + 4xy \\  \\  = ( {x}^{2}  + 16{y}^{2}  - 8xy) + ( {x}^{2}  +  16{y}^{2}   + 8xy) + 4xy \\  \\  =  2{x}^{2} + 32{y}^{2} + 4xy

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Answered by chanduvelagada2004
1

Answer:

  • (-x-4y)^2+(-x+4y)^2+4xy
  • (x+4y)^2+(-x+4y)^2+4xy
  • x^2+16y^2+4xy

Step-by-step explanation:

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