Question

plzzzzzzz help me insolving this question.​

Answer 1

Answer:

It's too simple dear...

Step-by-step explanation:

Sinx + cosecx = 2

Sinx + (1/Sinx) = 2

Multiply Sinx both sides...

(Sinx^2) +1 = 2Sinx

(Sinx^2) - 2Sinx + 1 = 0

(Sinx - 1)^2 = 0

So, Sinx = 1

And therefore Cosecx = (1/Sinx) = 1

So, Sinx^2 + Cosecx^7 = (1)^2 +(1)^7 = 2.....

Thanks...

Answer 2

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Sinx + cosecx = 2

Sinx + (1/Sinx) = 2

Multiply Sinx both sides...

(Sinx^2) +1 = 2Sinx

(Sinx^2) - 2Sinx + 1 = 0

(Sinx - 1)^2 = 0

So, Sinx = 1

And therefore Cosecx = (1/Sinx) = 1

So, Sinx^2 + Cosecx^7 = (1)^2 +(1)^7 = 2.....

Thanks...