Plzzzzzzz help me to factorize fhis.....
4y^2- 4yx + x^2- 9z^2
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Answer:
(2y-x+3z)(2y-x-3z)
Explanation:
4y²-4yx+x²-9z²
= [(2y)²-2*2y*x+x²]-(3z)²
=(2y-x)²-(3z)²
______________________
We know the algebraic identity:
a²-b² = (a+b)(a-b)
_____________________
=[(2y-x)+3z][(2y-x)-3z]
=(2y-x+3z)(2y-x-3z)
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