Question

plzzzzzzz plzzzzzzz plzzzzzzz give the ans. of this question​

Answer 1

hey mate..:-

find here

2^2x -10. 2^x + 16

=2^2x -8.2^x -2.2^x +16

=2^2x (2^x -8 )-2(2^x-8)

(2^2x-2)(2^x-8)

i hopes its helps u

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@Abhi❤❤

Answer 2

Answer:

It's too simple dear

Actually put 2^x = y...

So quadratic is y^2 - 10y +16 =0

..

Roots are 2 and 8...

So 2^x = 2...=> x= 1....

And 2^x = 8 => x= 3....

Answered by an IIT JEE ASPIRANT and all India mathematics Olympiad topper in class 10th... Look at my profile once...