Question

plzzzzzzz prove it.....

Answer 1

hey your answer dude
plz mark the brainliest
dfgh ☺️☺️

Answer 2

Heya there !!!
Here is the answer you were looking for:
${( \frac{ {x}^{a} }{ {x}^{b} } )}^{ \frac{1}{ab} } \times {( \frac{ {x}^{b} }{ {x}^{c} } )}^{ \frac{1}{bc} } \times {( \frac{ {x}^{c} }{ {x}^{a} } )}^{ \frac{1}{ca} } = 1 \\ \\ {( {x}^{a - b} )}^{ \frac{1}{ab} } \times {( {x}^{b - c} )}^{ \frac{1}{bc} } \times {( {x}^{c - a} )}^{ \frac{1}{ca} } = 1 \\ \\ {x}^{ \frac{a - b}{ab} } \times {x}^{ \frac{b - c}{bc} } \times {x}^{ \frac{c - a}{ca} } = 1 \\ \\ {x}^{ \frac{a - b}{ab} + \frac{b - c}{bc} + \frac{c - a}{ca} } = 1 \\ \\ {x}^{ \frac{c(a - b) + a(b - c) + b(c - a)}{abc} } = 1 \\ \\ {x}^{ \frac{ac - bc + ab - ac + bc - ab}{abc} } = 1 \\ \\ {x}^{ \frac{0}{abc} } =1 \\ \\ {x}^{0} = 1 \\ \\ 1 = 1$

Hence proved


Hope this helps!!!

If you have any doubt regarding to my answer, please ask in the comment section ^_^

@Mahak24

Thanks....
☺☺