Question

plzzzzzzz sis or bri

Answer 1

Hey !!!

2x = sec¢---1) and tan¢ = 2/x-----2)

adding 1) and 2) we get

sec¢ + tan¢ = 2x + 2/x

sec¢ + tan¢ = 2(x+1/x) ------3 )

and substracting 1) to 2)

sec¢ - tan¢ = 2x - 2/x

sec¢ - tan¢ = 2(x-1/x) -------4)

multiplying 3) and 4)

(sec¢ + tan¢)(sec¢ - tan¢) = 2(x+ 1/x) 2(x-1/x)

sec²¢ - tan²¢ = 4(x²-1/x² )

1/2 = 2(x² - 1/x²)

hence 2(x² -1/x² )= 1/2 Answer

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Hope it helps you !!!

@Rajukumar111

Answer 2

Answer:

2x = sec¢---1) and tan¢ = 2/x-----2)

adding 1) and 2) we get

sec¢ + tan¢ = 2x + 2/x

sec¢ + tan¢ = 2(x+1/x) ------3 )

and substracting 1) to 2)

sec¢ - tan¢ = 2x - 2/x

sec¢ - tan¢ = 2(x-1/x) -------4)

multiplying 3) and 4)

(sec¢ + tan¢)(sec¢ - tan¢) = 2(x+ 1/x) 2(x-1/x)

sec²¢ - tan²¢ = 4(x²-1/x² )

1/2 = 2(x² - 1/x²)

hence 2(x² -1/x² )= 1/2 Answer