Question

plzzzzzzz solve it....​

Answer 1

$\boxed{\rm{\color{#ff99ff}{Power (P)= \frac{Potential \: Difference(V)}{Resistance(R)}}}}$

• Resistance is fixed. So, R=R'
• Potential difference is halfed in second case. So, V÷2 = V'

• $\rm P' = \frac{V'}{R'} = \frac{ \frac{V}{2} }{R}$
• $\rm P' = \frac{V}{2R}$
• $\rm \frac{P}{P'} = \frac{ \frac{V}{R} }{ \frac{V}{2R} } = \frac{1}{2}$
• $\rm P' = 2P$

New Power(P') will become $\sf \red{(a)~double}$.

Answer 2

$\boxed{\rm{\color{#ff99ff}{Power (P)= \frac{Potential \: Difference(V)}{Resistance(R)}}}}$

Resistance is fixed. So, R=R'

Potential difference is halfed in second case. So, V÷2 = V'

$\rm P' = \frac{V'}{R'} = \frac{ \frac{V}{2} }{R}$

$\rm P' = \frac{V}{2R}$

$\rm \frac{P}{P'} = \frac{ \frac{V}{R} }{ \frac{V}{2R} } = \frac{1}{2}$

$\rm P' = 2P$

New Power(P') will become $\sf \green{(a)~double}$.