Plzzzzzzz solve it .....full explanation....... otherwise get lost
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Given
p = (2,1)
to find new coordinate
x = acos@ + bsin@
since
@ = 30°
(a,b) = (1,2)
x = 2sqrt3/2 + 1/2
x = (2sqrt3 + 1)/2
For y
y = acos@ - bsin@
y = 1cos30 - 2sin30
y = (-2 + sqrt3)/2
so option B is right
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