Question

plzzzzzzzz ans buddy ♥♥♥

very
important hurrry up

50 marks

Answer 1

First of all refer to the above attachment

We found that

ab = 14 - b. .....(1)

a - b = -2 .....(2)

We know that,

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab \\ \\ from \: eq \: (1) \: and \: (2) \\ \\ {( - 2)}^{2} = {a}^{2} + {b}^{2} - 2(14 - b) \\ \\ 4 = {a}^{2} + {b}^{2} - 28 + 2b \\ \\ 4 + 28 = {a}^{2} + {b}^{2} + 2b \\ \\ 32 = {a}^{2} + {b}^{2} + 2b \\ \\ {a}^{2} + {b}^{2} = 32 - 2b$

NOTE :-

It is the answer according to the conditions qiven in the question.

If you want the exact answer that will be free from any variable then there must be the change in the question as suggested in the comment box.

Answer 2

We found that,




$ab = 14 - b. .....(1) \\ \\ a - b = -2 .....(2)$






By the given condition,





$\begin{lgathered}{(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab \\ \\ from \: eq \: (1) \: and \: (2) \\ \\ {( - 2)}^{2} = {a}^{2} + {b}^{2} - 2(14 - b) \\ \\ 4 = {a}^{2} + {b}^{2} - 28 + 2b \\ \\ 4 + 28 = {a}^{2} + {b}^{2} + 2b \\ \\ 32 = {a}^{2} + {b}^{2} + 2b \\ \\ {a}^{2} + {b}^{2} = 32 - 2b \\\end{lgathered} \:$