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Plzzzzzzzz guys help me ......... Plzzzz............
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IN ΔAOB AND ΔAOD
AO=AO (COMMON)
AB=AD (ALL SIDES OF RHOMBUS ARE EQUAL)
∠AOB=∠AOD=90°(DIAGONALS PERPENDICULARLY BISECT EACH OTHER)
ΔAOB≅ΔAOD (RHS)
∠OAB=∠OAD (CPCT)
SIMILARLY U CAN PROVE OTHER ΔS CONGRUENT AND BY CPCT PROVE THAT THE DIAGONALS BISECT THE ANGLES
Step-by-step explanation:
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