Question

plzzzzzzzz help............... ​

Answer 1

$\sf\underline{\purple{\:\:\:\: Given\:\:\:\:}}$

$\sf\bullet Median\:of\:data=78\\ \\ \sf\:\:\:\:\bullet\:\:Data\:is\\ \\ \sf\:\: 44,\:47,\:63,\:x+13,\:87\:,93\:,99\:,110$

Now we have to find the value of x in the given data

$\sf\bullet{\purple{Number\:of\: observation=8(even\: number)}}$

$\boxed{\sf{Median=\dfrac{\bigg(\dfrac{n}{2}\bigg){}^{th}\:term+\bigg (\dfrac{n}{2}+1 \bigg){}^{th}\:term}{2}}}$

Where n is the total number of observation

$\sf\underline{\red{\:\:\:\: Solution\:\:\:\:}}$

$\sf:\implies 78=\dfrac{\bigg(\dfrac{8}{2}\bigg){}^{th}term+\bigg(\dfrac{8}{2}+1\bigg){}^{th}\:term}{2}\\ \\ \sf:\implies 78=\dfrac{\bigg(\dfrac{8}{2}\bigg){}^{th}term+\bigg(\dfrac{10}{2}\bigg)th\:term}{2}\\ \\ \sf\implies78= \dfrac{4th\:term+5th\:term}{2}\\ \\ \sf\bullet 4th\:term=x+13\\ \\ \sf\bullet 5th\:term=87\\ \\ \sf:\implies 78=\dfrac{x+13+87}{2}\\ \\ \sf:\implies 78\times 2=x+100\\ \\ \sf:\implies 156=x+100\\ \\ \sf:\implies x=156-100\\ \\ \sf:\implies x=56$

The value of x is 56

So 4th observation=56+13= 69

$\huge\mathfrak{\pink{x=56}}$

Answer 2

Answer:

$Medianofdata=78∙Datais44,47,63,x+13,87,93,99,110</p><p></p><p>Now we have to find the value of x in the given data</p><p></p><p>\sf\bullet{\purple{Number\:of\: observation=8(even\: number)}}∙Numberofobservation=8(evennumber)</p><p></p><p>\boxed{\sf{Median=\dfrac{\bigg(\dfrac{n}{2}\bigg){}^{th}\:term+\bigg (\dfrac{n}{2}+1 \bigg){}^{th}\:term}{2}}}Median=2(2n)thterm+(2n+1)thterm</p><p></p><p>Where n is the total number of observation</p><p></p><p>\sf\underline{\red{\:\:\:\: Solution\:\:\:\:}}Solution</p><p></p><p>\begin{gathered}\sf:\implies 78=\dfrac{\bigg(\dfrac{8}{2}\bigg){}^{th}term+\bigg(\dfrac{8}{2}+1\bigg){}^{th}\:term}{2}\\ \\ \sf:\implies 78=\dfrac{\bigg(\dfrac{8}{2}\bigg){}^{th}term+\bigg(\dfrac{10}{2}\bigg)th\:term}{2}\\ \\ \sf\implies78= \dfrac{4th\:term+5th\:term}{2}\\ \\ \sf\bullet 4th\:term=x+13\\ \\ \sf\bullet 5th\:term=87\\ \\ \sf:\implies 78=\dfrac{x+13+87}{2}\\ \\ \sf:\implies 78\times 2=x+100\\ \\ \sf:\implies 156=x+100\\ \\ \sf:\implies x=156-100\\ \\ \sf:\implies x=56\end{gathered}:⟹78=2(28)thterm+(28+1)thterm:⟹78=2(28)thterm+(210)thterm⟹78=24thterm+5thterm∙4thterm=x+13∙5thterm=87:⟹78=2x+13+87:⟹78×2=x+100:⟹156=x+100:⟹x=156−100:⟹x=56</p><p></p><p>The value of x is 56</p><p></p><p>So 4th observation=56+13= 69</p><p></p><p>$