plzzzzzzzz solve it bro
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xnxxsexy:
sakshi try
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Answered by
1
a.t.q.
x= 1
by putting value of x in eq.
(l)^2+1+k=0
1+1+k=0
2+k=0
k=-2
x= 1
by putting value of x in eq.
(l)^2+1+k=0
1+1+k=0
2+k=0
k=-2
Answered by
5
⭐Hey here is your answer ⭐
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x - 1 = 0
x = 1
P(x) = x² + x + k
P(1) = 1² + 1 + k
= 1 + 1 + k
= 2 + k
k = -2
✔️✔️Therefore the value of k is -2..........
___________________________
___________________________
I HOPE IT WILL HELP YOU☺️
Thank you☺️✌️
_______________________
_______________________
x - 1 = 0
x = 1
P(x) = x² + x + k
P(1) = 1² + 1 + k
= 1 + 1 + k
= 2 + k
k = -2
✔️✔️Therefore the value of k is -2..........
___________________________
___________________________
I HOPE IT WILL HELP YOU☺️
Thank you☺️✌️
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