Question

plzzzzzzzz solve this

Answer 1

==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================


${2}^{x } = {4}^{y} = {8}^{z}$

${2}^{x} = {2}^{2y} = {2}^{3z}$

So, x = 2y = 3z (since all bases are same)

=> y = x/2 and z = x/3

Also, we get, 4 y = 4(x/2) = 2x.

Now, 1/2x + 1/4y + 1/4z = 4

=> 1/2x + 1/2x + 1/4x/3 = 4

=> 1/2x + 1/2x + 3/4x = 4

=> (2+2+3 / 4x) = 4

=> 7/4x = 4

=> 7 = 16 x

=> x = 7/16.



==================================

*⃣ WHAT HAVE YOU LEARN ?? *⃣

➡ We have to apply our mind from all sides while we will proceed forward.

➡ Intelligent solutions have a long lasting good effect on the subject teacher's mind.

➡ If you can, you can do some shortcuts to proceed more swiftly in case of any numericals, here, from "LAWS OF INDICES".



==================================

⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐

==================================

Answer 2

2^x=4^y=8^z 


2^x = 2^2y = 2^3z

So, x = 2y = 3z (since all bases are same) 

=> y = x/2 and z = x/3 

Also, we get, 4 y = 4(x/2) = 2x. 

Now, 1/2x + 1/4y + 1/4z = 4

=> 1/2x + 1/2x + 1/4x/3 = 4

=> 1/2x + 1/2x + 3/4x = 4

=> (2+2+3 / 4x) = 4

=> 7/4x = 4

=> 7 = 16 x

=> x = 7/16.