English, asked by vikashkumar199, 1 year ago

plzzzzzzzz solve this immediately​

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Answered by IamIronMan0
1

Explanation:

Denominator has square term you can guess there may be

  \int \frac{x {e}^{x} +  {e}^{x}  -  {e}^{x}  }{(1 + x) {}^{2} } dx \\ \\   = \int \frac{ {e}^{x}  (1 + x )  -  {e}^{x}  }{(1 + x) {}^{2} } dx \\  \\  = \int \frac{ (\frac{d}{dx} {e}^{x})  (1 + x )  -  {e}^{x}  \frac{d}{dx}(1 + x)  }{(1 + x) {}^{2} } dx \\ \\   =  \int d( \frac{ {e}^{x} }{1 + x} ) \\  \\  =  \frac{ {e}^{x} }{1 + x} +c

For way seeing these kind of hints is only practice more questions

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