plzzzzzzzz solveeeee
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Given diagonal length=8cm
In a square diagonal bisect each other and equal .
So, By phythagoreas theorem
4^2+4^2=side^2
16+16=side^2
=>side=√32
=>side=4√2
, perimeter of square 4×side
so, putting value we got
=4×4√2
=16√2
So, ur answer is 16√2
Answered by
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Length of diagonal =8cm
As length of all sides of a square are equal
the
∆ABC WILL BE A RIGHT ISOCELES TRIANGLE
AND ANGLE ABC =90°
SO ACCORDING TO
PYTHAGORAS BABA
AC^2=AB^2+BC^2
AS ALL SIDES ARE EQUAL
AB=BC
SO
AC=8 (DIAGONAL)
AC^2=64
64=2AB^2
32=AB^2
√32=AB
SO
PERIMETER
OF A SQUARE = SIDE ×4
=√32 ×4
=16√2
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