Math, asked by jacky14, 1 year ago

plzzzzzzzz solveeeeeeee thisssssss

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Answers

Answered by jejwje
1
I hope this will help you
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jejwje: Mark it as brainlist
jacky14: why minus root 2 is become also root2
jejwje: What do you want to ask
jacky14: what happen to minus 2
jejwje: See there minus does'nt matter . I wrote 2 as the whole square of route 2
jejwje: because square of route 2 is 2
jacky14: thanx
Answered by wishi
5
hey User !!

⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜⚜

here's your
Solution
⬇⬇⬇⬇

 {a}^{3}  - 2 \sqrt{2}  \:  {b}^{3}  \\  =  {a}^{3}  - ( \sqrt{2})^{2}  \times  \sqrt{2}  \times  {b}^{3}  \\  =  {a}^{3}  - ( \sqrt{2} )^{3}  \times b {}^{3}  \\  =( a -  \sqrt{2} b) \:  { {a}^{2} + a \sqrt{2} b + ( -  \sqrt{2}  b) ^{2} } \\  = (a -  \sqrt{2} b)( {a}^{2}  +  \sqrt{2} ab + 2b ^{2} )

I
hope
this helps
you
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