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rishit210:
what is the shape of the hold
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Given Volume of gold in the wire = 1.1cm^3.
Given Diameter of the wire d = 0.1mm
The radius of the wire r = d/2
= 0.05mm.
Now,
The volume of the gold in wire = Volume of the wire
1.1cm^3 = pir^2 * h
1.1 * 1000mm^3 = 22/7 * (0.05)^2 * h
1100 = 22/7 * 0.0025 * h
1100 * 7 = 22 * 0.0025 * h
7700 = 0.055 * h
h = 140000mm.
h = 140000 * 0.001 m
= 140m.
Therefore the length of the wire = 140m.
Hope this helps!
Given Diameter of the wire d = 0.1mm
The radius of the wire r = d/2
= 0.05mm.
Now,
The volume of the gold in wire = Volume of the wire
1.1cm^3 = pir^2 * h
1.1 * 1000mm^3 = 22/7 * (0.05)^2 * h
1100 = 22/7 * 0.0025 * h
1100 * 7 = 22 * 0.0025 * h
7700 = 0.055 * h
h = 140000mm.
h = 140000 * 0.001 m
= 140m.
Therefore the length of the wire = 140m.
Hope this helps!
Answered by
1
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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