Question

plzzzzzzzz zzz help me.... ​

Answer 1

$\large{\underline{\underline{\sf{\blue{Correct \: Question-}}}}}$

x + y = 15 .... (1)

x - y = 3 .... (2)

$\large{\underline{\underline{\sf{\pink{To \: Find-}}}}}$

Values of x & y.

$\large{\underline{\underline{\sf{\orange{Solution-}}}}}$

Subtracting equation (1) from equation (2),

$\mathtt{x {\cancel{+ y}} = 15 \: .... \: (1)} \\ \\ \mathtt{x {\cancel{- y}} = 3 \: .... \: (2)} \\ ............................... \\ \mathtt{2x = 18}$

$:\implies\mathtt{2x = 18} \\ \\ :\implies\mathtt{x = \dfrac{\cancel{18}}{\cancel{2}}} \\ \\ \boxed{:\implies\mathfrak\red{x = 9}}$

Substituting x = 9 in equation (1),

$:\implies\mathtt{x + y = 15 \: .... \: (1)} \\ \\ :\implies\mathtt{9 + y = 15} \\ \\ :\implies\mathtt{y = 15 - 9} \\ \\ \boxed{:\implies\mathfrak\green{y = 6}}$

Therefore,

$\sf\star \: \underbrace\purple{x \: = \: 9 \: , \: y \: = \: 6} \: \star$

Hence,

Values of x & y are 9 & 6.

Answer 2

$\large{\underline{\underline{\sf{\green{Correct \: Question-}}}}}$

x + y = 15 .... (1)

x - y = 3 .... (2)

$\large{\underline{\underline{\sf{\red{To \: Find-}}}}}$

Values of x & y.

$\large{\underline{\underline{\sf{\orange{Solution-}}}}}$

Subtracting equation (1) from equation (2),

$\mathtt{x {\cancel{+ y}} = 15 \: .... \: (1)} \\ \\ \mathtt{x {\cancel{- y}} = 3 \: .... \: (2)} \\ ............................... \\ \mathtt{2x = 18}$

$:\implies\mathtt{2x = 18} \\ \\ :\implies\mathtt{x = \dfrac{\cancel{18}}{\cancel{2}}} \\ \\ \boxed{:\implies\mathfrak\orange{x = 9}}$

Substituting x = 9 in equation (1),

$:\implies\mathtt{x + y = 15 \: .... \: (1)} \\ \\ :\implies\mathtt{9 + y = 15} \\ \\ :\implies\mathtt{y = 15 - 9} \\ \\ \boxed{:\implies\mathfrak\pink{y = 6}}$

Therefore,

$\sf\star \: \underbrace\green{x \: = \: 9 \: , \: y \: = \: 6} \: \star$

Hence,

Values of x & y are 9 & 6.