Question

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Answer 1

$\underline{\orange{\bf Given :-}}$

Length of rectangle = 8 m

Breadth of rectangle = 6 m

$\underline{\orange{\bf To \: Find :-}}$

Length of diagonal

$\underline{\orange{\bf Solution :-}}$

We have,

Length of rectangle = 8 m

Breadth of rectangle = 6 m

We know that,

$\boxed{\sf Hypotenuse^{2} = Perpendicular^{2} + Base^{2}} \: \: \: [\bf Pythagoras \: theorem ]$

Substituting the values of perpendicular and base we get,

$\implies$Hypotenuse^2 = 6^2 + 8^2

$\implies$Hypotenuse^2 = 36 + 64

$\implies$Hypotenuse^2 = 100

$\implies$Hypotenuse = $\bf\sqrt{100}$

$\implies$Hypotenuse = 10 m

—:: Hence, Option d is correct.

Answer 2

Solution:−

We have,

Length of rectangle = 8 m

Breadth of rectangle = 6 m

We know that,

$\boxed{\sf Hypotenuse^{2} = Perpendicular^{2} + Base^{2}} \: \: \: \\ \bf [Pythagoras \: theorem ]$

Substituting the values of perpendicular and base we get,

$\longrightarrow$ Hypotenuse² = 6² + 8²

$\longrightarrow$ Hypotenuse² = 36 + 64

$\longrightarrow$ Hypotenuse² = 100

$\longrightarrow$ Hypotenuse= $\bf\sqrt{100}$

$\longrightarrow$ Hypotenuse = 10 m

Hence, Option d is correct.