Math, asked by chinku28, 11 months ago

plzzzzzzzzz answer it fast quick.​

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Answered by Anonymous
24

PQ॥ST and QR is transversal

hence ,

angle PQR = angle TRQ

X + 28 = 65

X = 65 - 28

X = 37 degree

IN Triangle PQS

X + Y + angle SPQ = 180 degree

37 + Y + 90 = 180

Y = 180 - 127

Y = 53 degree

X = 37 degree

Y = 57 degree

#ALLENITE ❤


Anonymous: Thanks
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Answered by Nazreen13
1

consider triangle SQR.

<QRS=180-65(LINEAR PAIR)

<QRS=115

so, <QSR=180-(28+115)

<QSR=37

Now consider, triangle PSQ

<PQS=<QSR(PS parallel to QR)

<PQS=37=X

<PSQ=180-(37+90)

<PSQ=53=y

hope it helps..

u can clarify any doubts

please mark it as brainleist

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