plzzzzzzzzz answer the question whose anwer is fully correct i will appreciate himm........
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Area of shaded region is 66.5cm^2. you can easily find out area of smaller circle. Then find Area of triangle that would be 0.5×14×7. then minus it from Semicircular area. Then sum up the shaded area.
How to proof question no. 29
Note- I have named triangle ABE instead of ABC so don't confuse.
Use opplonius theorem
proof =>
Draw a median of BE. Let's call it AC
see...
BD can be written as BE/3
CE can be written as BE/3
But BE = AB
BD = AB/3
CE = AB/3
then Applying Opplionus theorem in ∆ABC
AB^2 + AC^2 = 2(AD^2 + BD^2)
(7AB^2/9 ) + AC^2 = 2AD^2---------1
Applying Opplionus theorem in∆ADC
AD^2 + AE^2 = 2(AC^2+CE^2)
AC^2 = (9AD^2+7AB^2)/18
Replacing AC^2 in equations 1
(7AB^2)/9 +(9AD^2+7AB^2)/18 = 2AD^2
21AB^2 = 27AD^2
7AB^2 = 9AD^2
How to proof question no. 29
Note- I have named triangle ABE instead of ABC so don't confuse.
Use opplonius theorem
proof =>
Draw a median of BE. Let's call it AC
see...
BD can be written as BE/3
CE can be written as BE/3
But BE = AB
BD = AB/3
CE = AB/3
then Applying Opplionus theorem in ∆ABC
AB^2 + AC^2 = 2(AD^2 + BD^2)
(7AB^2/9 ) + AC^2 = 2AD^2---------1
Applying Opplionus theorem in∆ADC
AD^2 + AE^2 = 2(AC^2+CE^2)
AC^2 = (9AD^2+7AB^2)/18
Replacing AC^2 in equations 1
(7AB^2)/9 +(9AD^2+7AB^2)/18 = 2AD^2
21AB^2 = 27AD^2
7AB^2 = 9AD^2
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