Chemistry, asked by nasheera2, 1 year ago

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Answered by dattahari09
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Ans) a option

moles of complex =0.319/266.5=0.001196 moles or

1.196 Milli moles of complex

Milli moles of NaOH =MV

0.125x28.5 =3.56

1.196 Milli moles of complex required

3.665 Milli moles of NaoH

1 mole of complex required 3moles of NaoH

NaoH reacted with CL- ions which are present out side of complex NaOH need 3 moles of CL- (in water becomes HCl) in a) option 3 Cl outside of comp.

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