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moles of complex =0.319/266.5=0.001196 moles or
1.196 Milli moles of complex
Milli moles of NaOH =MV
0.125x28.5 =3.56
1.196 Milli moles of complex required
3.665 Milli moles of NaoH
1 mole of complex required 3moles of NaoH
NaoH reacted with CL- ions which are present out side of complex NaOH need 3 moles of CL- (in water becomes HCl) in a) option 3 Cl outside of comp.
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