plzzzzzzzzzz anrser my question who anser first i will mark them brainlist
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Hi Friend!
Given,
Isosceles right angled triangle,
Length of equal sides = 10 cm
In right angled triangle,
Hypotenuse² = side² + side²
hyp² = 10² + 10²
hyp² = 100+100
hyp² = 200
hyp = √200
hyp = 10√2 cm
Area of isosceles right angled triangle = ½ × base × height
= ½ × 10 × 10
= 50 cm²
Perimeter of the triangle = sum of all sides
= 10 + 10 + 10√2
= 20 + 10(1.414)
= 20 + 14.14
= 34.14 cm
Hope it helps
Given,
Isosceles right angled triangle,
Length of equal sides = 10 cm
In right angled triangle,
Hypotenuse² = side² + side²
hyp² = 10² + 10²
hyp² = 100+100
hyp² = 200
hyp = √200
hyp = 10√2 cm
Area of isosceles right angled triangle = ½ × base × height
= ½ × 10 × 10
= 50 cm²
Perimeter of the triangle = sum of all sides
= 10 + 10 + 10√2
= 20 + 10(1.414)
= 20 + 14.14
= 34.14 cm
Hope it helps
ksingh1:
bro
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