Question

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Answer 1

Answer:

w.k.t divisibility rule of 3 is addition of all the digits in the given number

therefore, the given no. is  497A

                            4+9+7+A=20+A should be divisible by 3

                      so A should be either 1 OR 3 OR 7

   and  divisibility rule of 4 is , the last two digits should be divisible by 4

            the given no is 562B

                             4 divide 20 , 24, 28

   so B can be either 0 or 4 or 8

from the above no the possible pair would be (1,0), (3,4), (7,8)