Question

plzzzzzzzzzz give the ansr with explanation​

Answer 1

Answer:

Here's the answer!!!!

Step-by-step explanation:

Here you go....

Answer 2

To Prove

4(BL² + CM²) = 5BC²

Here, since BL and CM are medians, we get

AL = AC/2 and AM = AB/2

Now, apply Pythagoras theorem in ΔABL,

AB² + AL² = BL²

⇒ AB² + (AC/2)² = BL²

⇒ AB² + AC²/4 = BL².........................(1)

Again, apply Pythagoras theorem in ΔAMC

AC² + AM² = CM²

⇒ Ac² + (AB/2)² = CM²

⇒ AC² + AB²/4 = CM².....................................(2)

In ΔABC,

AB² + AC² = BC² .................(3)

Now, add (1) and (2)

BL² + CM² = AB² + AC² + AB²/4 + AC²/4

Multiply by 4 on both sides,

⇒ 4(BL² + CM²) = 4AB² + 4AC² + AB² + AC²

⇒ 4(BL² + CM²) = 5AB² + 5AC²

⇒ 4(BL² + CM²) = 5(AB² + AC²)

⇒ 4(BL² + CM²) = 5BC² (From (3))

Hence Proved.