Math, asked by sujalbhardwaj66, 10 months ago

Plzzzzzzzzzz solve it​

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Answered by Sreesha
0

Answer:

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Step-by-step explanation:

The qus can be re-written as,

( 3.27ˣ.27 + 27.(3³)ˣ )      /      ( 3.(3³)ˣ.3² - 1/3 . 27ˣ.27 )

                     {taking 27ˣ common from numerator and denominator}

                                = [ 27ˣ(3.27+27) ]    /   [ 27ˣ (3.3² - 9) ]

                                = (3.27+27)  /   (3.3² - 9)

                    {taking 9 common from numerator and denominator}

                                 = 9(3.3 + 3) /  9(3 - 1)

                                = 9+3 / 2

                                = 6

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