Math, asked by sakshi345, 1 year ago

plzzzzzzzzzz Solve it

Attachments:

Answers

Answered by DaIncredible
0
Heya there !!!
Here is the answer you were looking for:
 \frac{7 \sqrt{3} }{ \sqrt{10} +  \sqrt{3}  }  -  \frac{2 \sqrt{5} }{ \sqrt{6}  +  \sqrt{5} }  -  \frac{3 \sqrt{2} }{ \sqrt{15}  + 3 \sqrt{2} }

On rationalizing the denominator we get,

 =  \frac{7 \sqrt{3} }{ \sqrt{10}  +  \sqrt{3} }  \times  \frac{ \sqrt{10}  -  \sqrt{3} }{ \sqrt{10} -  \sqrt{3}  }  -  \frac{2 \sqrt{5} }{ \sqrt{6}  +  \sqrt{5} }  \times  \frac{ \sqrt{6} -  \sqrt{5}  }{ \sqrt{6}  -  \sqrt{5} }  -  \frac{3 \sqrt{2} }{ \sqrt{15} + 3 \sqrt{2}  }  \times  \frac{ \sqrt{15} - 3 \sqrt{2}  }{ \sqrt{15} - 3 \sqrt{2}  }  \\  \\  =  \frac{7 \sqrt{3}( \sqrt{10} -  \sqrt{3}   )}{ {( \sqrt{10} )}^{2} -  {( \sqrt{3} )}^{2}  }  -  \frac{2 \sqrt{5}( \sqrt{6}   -  \sqrt{5}) }{ {( \sqrt{6} )}^{2} -  {( \sqrt{5} )}^{2}  }  -  \frac{3 \sqrt{2}( \sqrt{15}  - 3 \sqrt{2} ) }{ {( \sqrt{15}) }^{2} -  {(3 \sqrt{2}) }^{2}  }  \\  \\  =  \frac{7 \sqrt{30} - 21 }{10 - 3}  -  \frac{2 \sqrt{30}  - 10}{6 - 5}  -  \frac{3 \sqrt{30} - 18 }{15 - 18}  \\  \\  =  \frac{7 \sqrt{30}  - 21}{7}  - 2 \sqrt{30}  + 10 -  \frac{3 \sqrt{30}  - 18}{ - 3}  \\  \\  =  \sqrt{30}  - 21 - 2 \sqrt{30}  + 10 +  \sqrt{30}  - 6 \\  \\  =  - 21 + 10 - 6 \\  \\  =  - 27 + 10 \\  \\  =  - 17

Hope this helps!!!

If you have any doubt regarding to my answer, please ask in the comment section ^_^

@Mahak24

Thanks....
☺☺

DaIncredible: thanks for brainliest :-)
Answered by dfgh4
0
hello
hey your answer dude
plz mark the brainliest
dfgh ☺️☺️☺️
Attachments:

dfgh4: plz mark the brainliest
dfgh4: plz sakshi
Similar questions