Math, asked by ayushsinghbisht62005, 9 months ago

plzzzzzzzzzz solve sin^3A-cos^3A/sinA-cosA

Answers

Answered by 217him217

1

Answer:

Step-by-step explanation:

= (sin³A-cos³A) /(sinA-cosA)

=(sinA-cosA) (sin²A +2sinAcosA +Cos²A) /(sinA-cosA)

=(sin²A+cos²A+2sinAcosA)

=1+2sinAcosA

=1+sin2A

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