Math, asked by chamely2081985, 5 months ago

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Answers

Answered by fleyvengi
1

hope it helps..........

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Answered by abhisheksinghr81
2

Answer:

Here, 1)=Value of (1/sec^2A)+(1/cosec^2A) =1

2)=In this question, Value of (1/cos^2A)-(1/cot^2A)=1.

Step-by-step explanation:

Here, As per our given question,

=1)= (1/sec^2A)+(1/cosec^2A)

=(1/1/cos^2A)+(1/1/sin^2A) [As, secA=1/cosA, cosecA=1/sinA]

=cos^2A+sin^2A=1

As, sum of cos^2A and sin^2A=1.

2)=(1/cos^2A)-(1/cot^2A)

=(1/cos^2A)-(1/cos^2A/sin^2A) [As, cotA=cosA/sinA]

=(1/cos^2A)-(sin^2A/cos^2)

As here denominators of both are same,

=(1-sin^2A)/cos^2

=cos^2A/cos^2A [cos^2A+sin^2=1]

=1 (Answer).

Thank you.

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