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Here, 1)=Value of (1/sec^2A)+(1/cosec^2A) =1
2)=In this question, Value of (1/cos^2A)-(1/cot^2A)=1.
Step-by-step explanation:
Here, As per our given question,
=1)= (1/sec^2A)+(1/cosec^2A)
=(1/1/cos^2A)+(1/1/sin^2A) [As, secA=1/cosA, cosecA=1/sinA]
=cos^2A+sin^2A=1
As, sum of cos^2A and sin^2A=1.
2)=(1/cos^2A)-(1/cot^2A)
=(1/cos^2A)-(1/cos^2A/sin^2A) [As, cotA=cosA/sinA]
=(1/cos^2A)-(sin^2A/cos^2)
As here denominators of both are same,
=(1-sin^2A)/cos^2
=cos^2A/cos^2A [cos^2A+sin^2=1]
=1 (Answer).
Thank you.
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