Chemistry, asked by anjumashrafi57, 1 year ago

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Answered by Sudin
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a) First the metal carbonate ore is heated under the process of Calcination that is heating the ore under absence of Oxygen. From this we obtain their oxide which is then reduced by coke. Hence obtaining the metal.

b) In the extraction of copper from its Sulphide Ore, when ore is subjected to roasting some of it is oxidised to Cu2O which reacts with the remaining Cu2S to give copper metal. In this process, Cu2S behaves as reducing agent. 2Cu2S+3O2+heat→2Cu2O(s)+2SO2(g) 2Cu2O+Cu2S+heat→ 6Cu(s)+SO2(g) In electrolytic refining of copper, the impurities left behind at anode called anode mud contain valuable metals such as gold and silver which can be recovered in the native state.

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Answered by darkside10
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