Question

plzzzzzzzzzzzz answer this question ​

Answer 1

Step-by-step explanation:

use the herons formula which is √(s(s-a) (s-b) (s-c))

to find a triangle area

so here if you add two triangles ABD and DBC

you will get the answer

here s= semi perimeter of the triangle

and a, b, c are the sides of the triangles

I hope it could help you

Answer 2

Step-by-step explanation:

Area of quadrilateral ABCD = Area of Triangle ABD + Area of Triangle BCD

Now,

half perimeter of ABD, s1= (14+48+50)/2 cm = 56 cm

area of Triangle ABD

=

$\sqrt{s1(s1 - 14)(s1 - 48)(s1 - 50)}$

=

$\sqrt{56 \times 42 \times 8 \times 6}$

= 6 X 7 X 8 sqcm

= 336 sqcm

similarly,

half perimeter of BCD, s2= (50+78+112)/2 cm = 120 cm

area of Triangle BCD

=

$\sqrt{s2(s2 - 50)(s2 - 78)(s2 - 112)}$

=

$\sqrt{120 \times 70 \times 42\times 8}$

= 10 X 6 X 7 x 4 sqcm

= 1680 sqcm

so, area of quadrilateral ABCD

= 336 + 1680 sqcm

= 2016 sqcm