Question

plzzzzzzzzzzzz
answer this question quickly
I'll give you 50points
​

Answer 1

HERE IS YOUR ANSWER

(sec A+tan A)(1-sin A)

=sec A+tan A-sec A×sin A-tan A×sin A

=(1/cos A)+tan A-(1/cos A)(sin A)-(sin²A/cos A)

=[(1-sin²A)/cos A]+tan A-tan A

=cos²A/cos A

=cos A

Answer 2

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$( \sec( \alpha) + \tan( \alpha ) )(1 - \sin( \alpha ) ) \\ \\ = \sec( \alpha ) + \tan( \alpha ) - \sec( \alpha ) \times \sin( \alpha ) - \tan( \alpha ) \times \sin( \alpha ) \\ = \frac{1}{ \cos(a) } + \tan( \alpha ) - ( \frac{1}{ \cos( \alpha ) } ) ( \sin( \alpha ) ) - ( \frac{ { \sin }^{2} \alpha }{ \cos( \alpha ) }) \\ = ( \frac{1 - { \sin}^{2} a}{ \cos( \alpha ) }) + \tan( \alpha ) - \tan( \alpha ) \\ \\ = \frac{ { \cos }^{2} \alpha }{ \cos \alpha }$

$\huge \sf{ \underline{ \pink{ \huge{ \ { \: \: = \cos( \alpha ) \: \:{ \star { \star}}}}}}}</p><p>$