Question

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Answer 1

Given:  Two circles with centre’s O1  and O2. AB and CD are common tangents to the circles which intersect in P.

To Prove:  AB = CD

Proof:

AP = PC … .......................(1) (length of tangents drawn from an external point to the circle are equal)

PB = PD … ........................(2) (length of tangents drawn from an external point to the circle are equal)

Adding (1) and (2), we get

AP + PB = PC + PD

⇒  AB = CD