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Given: Two circles with centre’s O1 and O2. AB and CD are common tangents to the circles which intersect in P.
To Prove: AB = CD
Proof:
AP = PC … .......................(1) (length of tangents drawn from an external point to the circle are equal)
PB = PD … ........................(2) (length of tangents drawn from an external point to the circle are equal)
Adding (1) and (2), we get
AP + PB = PC + PD
⇒ AB = CD
To Prove: AB = CD
Proof:
AP = PC … .......................(1) (length of tangents drawn from an external point to the circle are equal)
PB = PD … ........................(2) (length of tangents drawn from an external point to the circle are equal)
Adding (1) and (2), we get
AP + PB = PC + PD
⇒ AB = CD
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