Question

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Solve : log10 + 1/3 log ( 3^(2√x) + 271 ) = 2

Answer 1

HELLO DEAR,

log_10(10) + 1/3log{3^(2√x) + 271} = 2

=> log_(10)[10*{3^(2√x) + 271}⅓] = 2

=> [10*{3^(2√x) + 271}⅓] = 10²

=> {3^(2√x) + 271}⅓ = 10

=> 3^(2√x) + 271 = 1000

=> 3^2√x = 729

=> 3^2√x = 3^6

on comparing both side we get,

=> 2√x = 6

=> √x = 3

=> x = 9

I HOPE IT'S HELP YOU DEAR,

THANKS

Answer 2

Answer:9

Step-by-step explanation:log_10(10) + 1/3log{3^(2√x) + 271} = 2

=> log_(10)[10*{3^(2√x) + 271}⅓] = 2

=> [10*{3^(2√x) + 271}⅓] = 10²

=> {3^(2√x) + 271}⅓ = 10

=> 3^(2√x) + 271 = 1000

=> 3^2√x = 729

=> 3^2√x = 3^6

on comparing both side we get,

=> 2√x = 6

=> √x = 3

=> x = 9