Question

PLZZZZZZZZZZZZZ SLOVE

Answer 1

Answer:

Step-by-step explanation:

6 boys and 6 girls sit in a row at random.

Then, the total number of arrangements of 6 boys and 6 girls = arrangement of 12 people = 12!

If the boys and girls sit alternatively

The required probability in that case would be :

6/12=1/2

Answer 2

Answer:

1/462

Step-by-step explanation:

Given: 6 boys and 6 girls.

∴ There are 12 persons.

All of them can be seated in 12! ways.So,Total number of possible events = 12!.

Now,

The arrangement of siting of 6 boys and 6 girls alternatively in a row may start with either a boy of girl. So,  2 types of starting are possible.

Type-1: BGBGBGBGBGBG

Type-2: GBGBGBGBGBGB

In each type 5 boys and 5 girls may take their positions in 6! ways. So, total the total number of favorable events will be:

= 2*6!*6!

Required probability = Favorable number of events/Possible number of events

= 2 * 6! * 6!/12!

= 5! * 6!/11!

= 3/(11 * 9 * 2 * 7)

= 1/462.

Hope it helps!