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Answer:
E is mid point of AC
Step-by-step explanation:
in ΔABC & ΔADC
∠A is common
DE ║ BC so
∠B = ∠D
∠C =∠E
As all angles are equal
=> ΔABC ≅ ΔADC
AD/AB = AE/AC
D is mid point of AB => AD = AB/2
=> 1/2 = AE/AC
=> AE = AC/2
=> E is mid point of AC
QED
Proved
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