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ABCD is a quadrilateral
To prove : ∠AOB= 1/2 (∠C+∠D)
AO and BO is bisector of A and B
∠1=∠2∠3=∠4...(1)
∠A+∠B+∠C+∠D=360
(Angle sum property)
1/2(∠A+∠B+∠C+∠D)=180...(2)
In △AOB
∠1+∠3+∠5= 1/2 (∠A+∠B+∠C+∠D)
∠1+∠3+∠5=∠1+∠3+ 1/2 (∠C+∠D)
∠AOB= 1/2(∠C+∠D)
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