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the soln to ur question
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∠AOD + ∠DOC + ∠COB = 180° (By linear pair axiom)
(x+10)° + (x)° + (x+20)° = 180°
3x° + 30° = 180°
3x° = 180° - 30°
x° = 150°/3°
x° = 50°
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☺☺☺ Hope this Helps ☺☺☺
(x+10)° + (x)° + (x+20)° = 180°
3x° + 30° = 180°
3x° = 180° - 30°
x° = 150°/3°
x° = 50°
_____________________________________________________
☺☺☺ Hope this Helps ☺☺☺
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