Math, asked by akshusurekha398562, 9 months ago

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Answers

Answered by etibrihaspati06
0

Answer:

First you will equate 2x^3+1 with 0

2x^3=-1

x^3=-1-2

x^3=-3

x=3cube root (here I will write 3cube root as 33 so don't get confused)

Now substitute the value x in the equation

2x^5+10x^4+6x^3+22^2+5x+1

2(3√3)^5+10(3√3)^4+6(3√3)^3+484+5(3√3)+1

2(3)(3√3)^2 + 10(3)(3√3) + 6(3) + 484 + 5(3√3) +1

6(3√3)^2 + 30(3√3) + 18 + 484 + 1 + 5(3√3)

6(3√3)^2 + 30(3√3) + 503 + 5(3√3)

I think this is relevant, but if there's any mistake I am sorry and if there is please tell me what was wrong

Thank you

Answered by aditi346454
0

Answer:

no it is not a not a factor of 2x³+1

i hope it will help u

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