Question

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Answer 1

$\huge{\bold{\underline{\underline{Solution}}}}$

$1).\: \dfrac{x+2}{6} -\Bigg(\dfrac{4(11-x)-3\times(1)}{12}\Bigg) = \dfrac{3x-4}{12}\\\\\implies \dfrac{x+2}{6} -\dfrac{(44-4x-3)}{12} = \dfrac{3x-4}{12} \\\\\implies \dfrac{x+2}{6} -\dfrac{ (41-4x)}{12} = \dfrac{3x-4} {12}\\\\\implies \dfrac{x+2}{6} = \dfrac{3x-4}{12}+ \dfrac{41-4x}{12} \\\\\implies \dfrac{x+2}{6} = \dfrac{3x-4+41-4x}{12} \\\\ \implies\dfrac{x+2}{6} = \dfrac{-x+37}{12} \\\\\implies 12(x+2) = 6(-x+37) \\\\ \implies 2(x+2)\: = \: 37\:-\:x \\\\ \implies 2x\:+\:4= 37\:-\:x \\\\ \implies 3x \: = \:33 \\\\\implies x=\dfrac{33}{3} \\\\\implies x\: = \:11$

$\bold{\large{\boxed{ x \: = \: 11}}}$

$\bold{\large{Thanks}}$

Answer 2

1 one had give correct