Question

plzzzzzzzzzzzzzzzzzzzzzzzz ans this ----
an object of 3cm high is place at the distance of 8cm from a concave mirror which produce a virtual image of4.5 cm ?????
draw ray diagram and explain it

Answer 1

hello....





▶Height of object (h) = 3 cm

▶Distance of object ( concave mirror )
(u) = -8 cm

▶Height of the virtual image formed (h') = 4.5
'v' =

- v/u = h'/h

v = - u × h'/h

v = - ( -8) × 4.5 / 3

v = 12 cm

▶Focal length of mirror =

1/f = 1/v + 1/u

1/f = 1/12 + 1/ -8

1/f = -1/24

1 × 24 = -f

24 = -f

f = -24 cm

Position of image (v) = 12 cm

Therefore the image is vertical and erect...




thank you....