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an object of 3cm high is place at the distance of 8cm from a concave mirror which produce a virtual image of4.5 cm ?????
draw ray diagram and explain it
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hello....
▶Height of object (h) = 3 cm
▶Distance of object ( concave mirror )
(u) = -8 cm
▶Height of the virtual image formed (h') = 4.5
'v' =
- v/u = h'/h
v = - u × h'/h
v = - ( -8) × 4.5 / 3
v = 12 cm
▶Focal length of mirror =
1/f = 1/v + 1/u
1/f = 1/12 + 1/ -8
1/f = -1/24
1 × 24 = -f
24 = -f
f = -24 cm
Position of image (v) = 12 cm
Therefore the image is vertical and erect...
thank you....
▶Height of object (h) = 3 cm
▶Distance of object ( concave mirror )
(u) = -8 cm
▶Height of the virtual image formed (h') = 4.5
'v' =
- v/u = h'/h
v = - u × h'/h
v = - ( -8) × 4.5 / 3
v = 12 cm
▶Focal length of mirror =
1/f = 1/v + 1/u
1/f = 1/12 + 1/ -8
1/f = -1/24
1 × 24 = -f
24 = -f
f = -24 cm
Position of image (v) = 12 cm
Therefore the image is vertical and erect...
thank you....
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