Question

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Answer 1

Answer:

in ∆ACE,

AE=AC

SO,<AEC=<ACE (isosceles triangle property)

by angle sum property,

<ACE+<AEC+<CEA=180

2<ACE=180-40=140

<ACE=<AEC=70

<BCE+<ECA+<ACF=180 (LINEAR PAIR)

<BCE=180-70-75=180-145

<BCE=35

in ∆BEC,

BY exterior angle property,

<AEC=<EBC+<ECB

<EBC=70-35=35

<EBC=35

WHEN <EBC=<BCE=35

by isosceles triangle property,

BE=CE

HOPE IT HELPS YOU.....

Answer 2

Answer:

here is your answer. . . . . . . . . . .