Math, asked by barbaras, 11 months ago

PM is a median prove that A(triangle PQM)=A (triangle PRM)​

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Answers

Answered by amitnrw
6

Answer:

BC : QR = 3:4

QR = 15

Step-by-step explanation:

ΔABC ≅ ΔPQR

=> AB/PQ  = BC/QR  =  √Area of ΔABC /√Area of ΔPQR

=>  BC/QR = √(Area of ΔABC/Area of ΔPQR)

=> BC/QR = √(9/16)

=> BC/QR  = 3/4

BC : QR = 3:4

in ΔPQR  RS is bisector of ∠PRQ

=> PS/QS  = PR/QR

=> 8/6  = 20/QR

=> QR = 15

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