PM=PN,PM perpendicular AB and PN perpendicular AC
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Answered by
78
In triangle APM and triangle APN
PN=PM ..(.given)
angle PNA = angle PMA ...(each 90 degree).
AP =AP (commom)
by RHS triangles are congruent.
by CPCT. AM = AN and angle PAM=angle PAN......
hope it's helpful..thanks
PN=PM ..(.given)
angle PNA = angle PMA ...(each 90 degree).
AP =AP (commom)
by RHS triangles are congruent.
by CPCT. AM = AN and angle PAM=angle PAN......
hope it's helpful..thanks
Gunnu26:
plz mark it as brilliant
Answered by
8
ΔAPN ≅ ΔAPM if In the figure, PM=PN, PM perpendicular AB and PN perpendicular AC
Step-by-step explanation:
Complete Question :
Show that AN = AM or ΔAPN ≅ ΔAPM
Comparing ΔAPN & ΔAPM
AP = AP ( common)
PN = PM ( given)
∠ANP = ∠AMP = 90°
=> AN = AM ( as AN² = AP² - PN² = AP² - PM² = AM²)
=> ΔAPN ≅ ΔAPM
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