Question

Po 1200 R=2% T= 2 years find iis amount and simple interest?​

Answer 1

Answer:

5/

Step-by-step explanation:

Principal(P)=Rs.1200

Amount(A)=Rs.1320

S.I.=A−P=Rs.1320−Rs.1200=Rs.120

Time(T)=2 years

Rate%=

P×T

S.I.×100

=

1200×2

120×100

=5% p.a.

Answer 2

Given:

• Principal = ₹1200
• Rate = 2%
• Time = 2 years.

To find:

Simple interest and Amount.

Solution:

Finding the Simple interest:

$= {\frac{1200×2×2}{100}}$

$\bold{\red{ = ₹48}}$

Now, finding the Amount:

$= 1200 + 48$

$\bold{\pink{= ₹1248}}$

Hence, the simple interest is ₹48 and Amount is ₹1248!!

Extra Information:

• $\mathtt{S.I. = \frac{P×R×T}{100}}$

• $\mathtt{Amount = Principal+Interest}$

• $\mathtt{P = \frac{S.I. × 100}{T×R}}$

• $\mathtt{R = \frac{S.I. × 100}{P×T}}$

• $\mathtt{T = \frac{S.I. × 100}{P×R}}$

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