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figure 6.45. CD I BA. Prove that
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Answer:Prove That Triangle APB is similar to triangle CPD.
Step-by-step explanation:AB is parallel to CD.
So Angle CDB is equal to angle DBA and
Angle CAB is equal to angle DCA.
By Angle Angle test of Similiarity,
Triangle APB is similar to triangle CPD.
Therefore,
AP/PC = BP/PD
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