Math, asked by khushinepal17, 1 year ago

PO
figure 6.45. CD I BA. Prove that
FIGURE 543​

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Answered by varadan04
1

Answer:Prove That Triangle APB is similar to triangle CPD.

Step-by-step explanation:AB is parallel to CD.

So Angle CDB is equal to angle DBA and

Angle CAB is equal to angle DCA.

By Angle Angle test of Similiarity,

Triangle APB is similar to triangle CPD.

Therefore,

AP/PC = BP/PD

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