Question

PO II BC such that AP =3.2 cm AO =4.8 cm and QC=9.6 cm find PB​

Answer 1

Answer:

PQ∥BC

⇒∠APQ=∠ABC

and∠AQP=∠ACB(corespondinganglearesame)

∴△APQ∼△ABC(AAcriteria)

hence,

AB

AP

=

AC

AQ

⇒

AP

AB

=

AQ

AC

⇒

AP

AB

−1=

AQ

AC

−1

⇒

AP

PB

=

AQ

QC

⇒

2.4

7.2

=

AQ

5.4

⇒AQ=1.8cm