Question

Po²¹⁰ has half life of 140d. In 1g Po²¹⁰ how many disintegration will take place every second ? [Avogadro's number = 6.023×10²³]

Answer 1

ANSWER

Given:

Half life of Po²¹⁰ = 140 d.

Avogadro's Number = 6.023 × 10²³

Step by step explanation:

Disintegration constant,

λ = $\frac{0.693}{T} = \frac{0.693}{140 \times 24 \times 60 \times 60}s {}^{ - 1}$

Number of atoms in 210 g Po²¹⁰ = Avagadro's number = 6.023 ×10²³

∴ Number of atoms in 1 g Po²¹⁰ ,

N = $\frac{6.023 \times 10 {}^{23} }{210}$

∴ Disintegration per second = activity = λN

= $\frac{0.693}{140 \times 24 \times 60 \times 60} \times \frac{6.023 \times 10 {}^{23} }{210}$

= $1.64 \times 10 {}^{14} dps$