Poem praise of mother by debasish mishra appreciation
Answers
Answer:
Given:
\textsf{Length of the roller is 1.5.m}Length of the roller is 1.5.m
\textsf{Diameter of the roller is1.4 m}Diameter of the roller is1.4 m
\underline{\textsf{To find:}}
To find:
\textsf{The curved surface area and area can be levelled in 200 revolutions}The curved surface area and area can be levelled in 200 revolutions
\underline{\textsf{Solution:}}
Solution:
\textsf{Diameter of the roller=1.4m}Diameter of the roller=1.4m
\implies\textsf{Radius of the roller=0.7m}⟹Radius of the roller=0.7m
\textsf{Curved surface area of the roller}Curved surface area of the roller
\mathsf{=2\,\pi\,r\,h}=2πrh
\mathsf{=2{\times}\dfrac{22}{7}{\times}0.7{\times}1.5}=2×
7
22
×0.7×1.5
\mathsf{=2{\times}22{\times}0.1{\times}1.5}=2×22×0.1×1.5
\mathsf{=3{\times}2.2}=3×2.2
\mathsf{=6.6}\,\textsf{square meters}=6.6square meters
\textsf{Area covered by the roller in 1 revolution}\mathsf{=1{\times}}\textsf{curved surfacce area of the roller}Area covered by the roller in 1 revolution=1×curved surfacce area of the roller
\textsf{Area covered by the roller in 200 revolution=200}\mathsf{\times}\textsf{curved surfacce area of the roller}Area covered by the roller in 200 revolution=200×curved surfacce area of the roller
\mathsf{=200{\times}6.6}=200×6.6
\mathsf{=1320}\;\textsf{square meters}=1320square meters
\underline{\textsf{Answer:}}
Answer:
\textsf{Curved surface area of the roller is 6.6 square meters}Curved surface area of the roller is 6.6 square meters
\textsf{Area covered by the roller in 200 revolutions 1320 square meters}Area covered by the roller in 200 revolutions 1320 square meters
Find more:
The curved surface area of a cylinder is 1320 cm² and its base had diameter 21 cm. Find the height and the volume of the cylinder.[Use π = 22/7]