Question

pogram to find the sum of left and right diagonal using array

Answer 1

#include<iostream>#include<conio.h>using namespace std;
int matrix[4][4];
int getarray()  {    for (int i = 0; i < 4; i++) {        for (int j = 0; j < 4; j++) {          std::cout <<"enter row "<<i+1<<" element "<<j+1<<endl;          std::cin >> matrix[i][j];        }      }    return 0;  }

int showarray()  {    for (int i = 0; i < 4; i++) {        for (int j = 0; j < 4; j++) {          std::cout <<matrix[i][j]<<'\t';          }        std::cout << '\n';      }    return 0;  }


int diagsum()  {      int sum1=0,sum2=0;      for(int i=0;i<4;i++)        {          sum1+=matrix[i][i];        }      for (int i = 4; i > 0; i--) {          sum2+=matrix[i][3-i];      }    std::cout<<"\n\nSum of 1st diagonal : "<<sum1;    std::cout<<"\nSum of 2nd diagonal : "<<sum2;    return 0;  }



int main()  {    std::cout << "Enter the array :" << '\n';    getarray();    std::cout << "\n\nThe array is :\n\n" << '\n';    showarray();    diagsum();    getch();    return 0;  }